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B
(2a+b+1)(2a+b−4)
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C
(2ab+1)(2a+b−4)
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D
(2a+b+1)(2a−4b+1)
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Solution
The correct option is B(2a+b+1)(2a+b−4) ⇒(2a+b)2−6a−3b−4 ⇒(2a+b)2−3(2a+b)−4 Let (2a+b)=x ⇒x2−3x−4 ⇒x2+x−4x−4 ⇒x(x+1)−4(x+1) ⇒(x+1)(x−4) Substitutingx=(2a+b) ⇒(2a+b+1)(2a+b−4)