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Question

Expand:(3a2b+5c)2

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Solution

We have (x+y+z)2=x2+y2+z2+2(xy+yz+zx)

Take x=3a,y=2b and z=5c

(3a2b+5c)2=(3a)2+(2b)2+(5c)2+2(3a×2b+(2b)×5c+5c×3a)

=9a2+4b2+25c2+2(6ab10bc+15ac)

=9a2+4b2+25c212ab20bc+30ac

(3a2b+5c)2=9a2+4b2+25c212ab20bc+30ac

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