The correct option is A 64 16x+43x^2 127x^3 #160; #160; ( 4 1 3x #160;) ^ 3 = 4 ^ 3 ( 1 3x #160;) #160;^ 3 3× 4× 1 3x (4 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Algebraic Identities

Expand : 4-...

Question

Expand : ${(4 - \frac{1}{3 x})}^{3}$

64 - \frac{16}{x} + \frac{4}{3 x^{2}} - \frac{1}{27 x^{3}}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

64 - \frac{19}{x} + \frac{4}{3 x^{2}} - \frac{1}{27 x^{3}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

64 - \frac{26}{x} + \frac{4}{3 x^{2}} - \frac{1}{27 x^{3}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

64 - \frac{29}{x} + \frac{4}{3 x^{2}} - \frac{1}{27 x^{3}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $64 - \frac{16}{x} + \frac{4}{3 x^{2}} - \frac{1}{27 x^{3}}$
${(4 - \frac{1}{3 x})}^{3}$
$= 4^{3} - {(\frac{1}{3 x})}^{3} - 3 \times 4 \times \frac{1}{3 x} (4 - \frac{1}{3 x})$
$= 64 - \frac{1}{27 x^{3}} - \frac{16}{x} + \frac{4}{3 x^{2}}$

Suggest Corrections

Similar questions

Factorize $\frac{8}{27} x^{3} + 1 + \frac{4}{3} x^{2} + 2 x$

3 x - \frac{4}{x} = 4

x \neq 0

27 x^{3} - \frac{64}{x^{3}}

3 x - \frac{4}{x} = 4

x \neq 0

27 x^{3} - \frac{64}{x^{3}}

27 x^{3} - \frac{64}{x^{3}}

\frac{3 x^{2} - x - 4}{9 x^{2} - 16} \div \frac{4 x^{2} - 4}{3 x^{2} - 2 x - 1}

Join BYJU'S Learning Program