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Byju's Answer
Standard XII
Mathematics
Higher Order Derivatives
Expand: y+ 1...
Question
Expand:
(
y
+
1
y
)
2
Open in App
Solution
(
y
+
1
y
)
2
=
y
2
+
1
y
2
+
2
×
y
×
1
y
=
y
2
+
1
y
2
+
2
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