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Question

Expand the following, using suitable identity.
(2a3bc)2

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Solution

We have, (2a3bc)2
Using identity
(a+b+c)2=a2+b2+c2+2ab+2bc+2ca,
we get
(2a3bc)2

=(2a)2+(3b)2+(c)2+2(2a)(3b)+2(3b)(c)+2(c)2a

=4a2+9b2+c212ab+6bc4ac

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