CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
651
You visited us 651 times! Enjoying our articles? Unlock Full Access!
Question

Expand using suitable identities
(2a3b)3

Open in App
Solution

We need to expand (2a3b)3
We know suitable identity is (xy)3=x33x2y+3xy2+y3
Here x=2a and y=3b
Therefore, value of (2a3b)3 is
=(2a)33(2a)2(3b)+3(2a)(3b)2(3b)3
=8a336a2b+54ab227b3

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Polynomial and Its General Form
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon