Expand the given expression using identitites:
${(a^{2} - b^{2})}^{2}$

a^{4} - a^{2} b^{2} + b^{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

a^{4} - 2 a^{2} b^{2} - b^{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

a^{4} - 2 a^{2} b^{2} + b^{4}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

a^{4} + 2 a^{2} b^{2} + b^{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $a^{4} - 2 a^{2} b^{2} + b^{4}$
Expanding using the identity $(a - b)^{2} = a^{2} + b^{2} - 2 a b$ , we get
$(a^{2} - b^{2})^{2} = (a^{2})^{2} + (b^{2})^{2} - 2 a^{2} b^{2}$
$= a^{4} + b^{4} - 2 a^{2} b^{2}$
$= a^{4} - 2 a^{2} b^{2} + b^{4}$

Suggest Corrections

Similar questions

a^{2} + 2 a b + b^{2} = (a + b)^{2}

x^{2} + 2 x + 1

a^{2} - 2 a b + b^{2} = (a - b)^{2}

x^{2} - 8 x + 16

(t + 3)^{2}

{(3 x - 5 y)}^{2}

Question 85 (xiii)

Expand the following, using suitable identities.

$(a^{2} + b^{2})^{2}$

Join BYJU'S Learning Program