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Question

Expand using identity : (3x+5y+2z)(3x−5y+2z)

A
16x212xz+4z225y2
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B
9x2+12xz+4z225y2
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C
22x2+12xz+4z2+25y2
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D
13x212xz+4z225y2
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Solution

The correct option is C 9x2+12xz+4z225y2
(3x+5y+2z)(3x5y+2z)
=(3x+2z+5y)(3x+2z5y)
=(3x+2z)2(5y)2 ...[Using a2b2=(a+b)(ab)]
=((3x)2+2(3x)(2z)+(2z)2)25y2 ....[Using (a+b)2=a2+2ab+b2]
=9x2+12xz+4z225y2

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