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Question

Expand (y+3x)3

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Solution

(y+3x)3=(y)3+(3x)3+3(y)(3x)(y+3x)
Using, (a+b)3=a3+b3+3ab(a+b)
=y3+27x39xy(y+3x)
=y3+27x3+9y2x27yx2

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