Expanded form of 243.7=(2×102)+(4×101)+ + (7×10−1)
A
(4×101)
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B
(3×101)
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C
(3×100)
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D
(3×102)
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Solution
The correct option is C(3×100) Using a0=1 and a−m=1am for a non-zero integer a and any integer m, we have 243.7=200+40+3+0.7 =(2×102)+(4×101)+(3×100)+710 =(2×102)+(4×101)+(3×100)+(7×10−1).