explain "h nu" in terms of sunlight as a factor of a chemical reaction

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$A c c o r d i n g t o M a x w e l l P l a n c k E = h ν T h a t m e a n s e n e r g y i s d i r e c t l y p r o p o t i o n a l t o f r e q u e n c y o f t h e l i g h t u s e d . E α ν E = h ν W h e r e h i s t h e P l a n c k' s c o n s \tan t P h o t o c h e m i c a l r e a c t i o n s u s e s s u n l i g h t w h o s e e n e r g y i s = h ν$
$F o r e x ., 6 C O_{2} + 6 H_{2} O \overset{h ν}{\to} C_{6} H_{12} O_{6} + 6 O_{2}$

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explain "h nu" in terms of sunlight as a factor of a chemical reaction

According to Maxwell PlanckE= hνThat means energy is directly propotional to frequency of the light used. E α νE = hνWhere h is the Planck's constantPhotochemical reactions uses sunlight whose energy is = hν For ex.,6CO2 +6 H2O →hν C6H12O6 + 6O2