Question

Explain hybridisation of central atom in $S{F}_6$.

Answer 1

In $S{F}_6$ the central sulphur atom has the ground state configuration,$3s^{2}3p^4$ one electron each from $3s$ and $3p$ orbitals is promoted to $3d$ orbitals These six orbitals get hybridised to form six $s{p}^3{d}^2$hybrid orbitals. Each of these $s{p}^3{d}^2$ hybrid orbitals overlaps with $2p$ orbital of fluorine to form $S-F$ bond. Thus, $S{F}_6$ molecule has octahedral structure.