Question

Explain hybridization of central atom in :$I{F}_3$

Answer 1

The hybridization of $I{F}_3$ can be determined by the number of lone pairs around iodine and the number of sigma bonds formed between I and F. Since the iodine has 7 valence electrons out of which 3 electrons form sigma bond with F atoms and left with forming 2 lone pair. Hence this shows that stearic number is 5 and therefore the hybridization is $s{p}^{3}d$ and the geometry is trigonal planar and the shape is T-shaped where the 2 F atoms are axial and one is at equatorial position.