Question

Explain hybridization of central atom in :$P{O}_4^{3-}$

Answer 1

In the given molecule, The P atom have 5 valence electrons. The hybridization can be determined by the number of sigma bonds and the number of lone pair. The number of sigma bond is 4 and the number of lone pairs is 0. This implies stearic number is 4 and hence the hybridization is $s{p}^3$ and the geometry and shape of the molecule is tetrahedral and two electrons are forming a double bond (1 sigma and 1 pi) and 3 electrons are forming 3 sigma bonds.