Question

Explain the non - liner shape of $H_{2}S$ and non planar shape of $PC{l}_3$ using valence shell electron pair repulsion theory.

Answer 1

Solution:

Shape of $H_{2}S$ molecule

In $H_{2}S$ molecule

* Number of bond pairs $=2$

* Number of bond pairs $=2$

$H_{2}S$ molecule is surrounded by total $4$ electron pairs. So, the hybridisation of the central atom in $H_{2}S$ molecule will be $s{p}^3$ . As two electron pairs are lone pairs and rest are bond pairs, so its shape is V or bent.



$H_{2}S$ molecule

$V-$ shape / Bent shape

Thus, the shpe of $H_{2}S$ is not linear.


Shape of $PC{l}_3$ molecule

In $PC{l}_3$ molecule:

* Number of bond pairs $=3$

* Number of lone pairs on central atom $=1$

$PC{l}_3$ molecule is surrounded by total $4$ electron pairs. So, the hybridisation of the central atom in $PC{l}_3$ molecule will be $s{p}^3$ . As one electron pair is lone pair and rest are bond pairs, so its shape is pyramidal.


Thus, the $PC{l}_3$ molecle is a non-planar molecule.