Explain the reaction of the following with ozone-
$C_{2} H_{4}$
$K I$
$H g$
$P b S O_{4}$

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Solution

(A) Reaction of $C_{2} H_{4}$ with ozone $\to$
Ethylene reacts with ozone to form mole ozonide of ethylene initially then reacts with $Z n / H_{2} O$ to form formaldehyde.
$C_{2} H_{4} O_{3} - ---- \to Z n / H_{2} O H C H O Formaldehyde$
(B) Reaction of $K I$ with ozone $\to$
Potassium iodide react with ozone to produce potassium iodate which on further rection with water gives potassium hydroxide.
$K I + 3 O_{3} ⟶ K I O_{3} + 3 O_{2}$
$K I O_{3} + H_{2} O ⟶ K O H + I_{2} + O_{2}$
(C) Reaction of $H g$ with ozone $\to$
When mercury oxidises by ozone, it produces Mercury (I) oxide.
$2 H g + O_{3} ⟶ {H g}_{2} O + O_{2}$
(D) Reaction of $P b S$ with ozone $\to$
Lead (II) sulfide react with ozone to produce lead (II) sulfate and oxygen. The reaction proceeds at room temperature.
$P b S + 4 O_{3} ⟶ P b S O_{4} + 4 O_{2}$

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