Explain the similarity and difference in two events, namely adding $N a O H$ to water and adding $C a O$ to water.

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Solution

With $N a O H$ , you are only dissolving the material, whereas $C a O$ reacts to make $C a (O H)_{2}$ . The calcium hydroxide has a lower solubility in water than $N a O H$ and so will precipitate out.
Adding $N a O H$ to water:
$N a O H + H_{2} O = N a^{+}$ and $O H^{-}$ ions. The reaction will be exothermic where heat will be released. Sodium hydroxide is considering a strong base and as such is able to completely and fully dissociate in aqueous solution.
Adding $C a O$ to water:
A lot of heat (exothermic reaction) is produced in the reaction, which may even cause the water to boil.

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