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Limiting Reagent or Reactant

Sulphuryl chl...

Question

Sulphuryl chloride $(S O_{2} C l_{2})$ reacts with water to give a mixture of $H_{2} S O_{4}$ and $H C l$ . Number of moles of $N a O H$ required to neutralize the solution formed by adding $1$ mol of $S O_{2} C l_{2}$ to excess water is:

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Solution

The correct option is D $4$
$S O_{2} C l_{2} + 2 H_{2} O \to H_{2} S O_{4} + 2 H C l$
$H_{2} S O_{4} \equiv 2 N a O H$
$2 H C l \equiv 2 N a O H = 4 N a O H$
Hence, the number of moles of $N a O H$ required to neutralize the solution formed by adding $1$ mol of $S O_{2} C l_{2}$ to excess water is $4$ .

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Similar questions

Sulfuryl chloride $(S O_{2} C l_{2})$ reacts with water to give a mixture of $H_{2} S O_{4}$ and HCl. How many moles of baryta would be required to neutralize the solution formed by adding 1 mole of $S O_{2} C l_{2}$ to excess of water ?

S O_{2} C l_{2}

(sulphuryl chloride) reacts with water to give a mixture of

H_{2} S O_{4}

and

H C l

. What volume of

0.2 M B a (O H)_{2}

is needed to completely neutralize

25

mL of

0.2 M S O_{2} C l_{2}

solution.

Q. Sulphuryl chloride

(S O_{2} C l_{2})

reacts with white phosphorus

(P_{4})

to give:

Q. Assertion :One mole of

S O_{2} C l_{2}

in aqueous solution is neutralised by 3 moles of

N a O H

. Reason: 3 moles of

H^{+}

are formed due to reaction with water.

Q. One mole of

S O_{2} C l_{2}

is dissolved in water and

C a (O H)_{2}

is added to neutralise acidic solution. Number of moles of

C a (O H)_{2}

required is :

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Sulphuryl chloride (SO2Cl2) reacts with water to give a mixture of H2SO4 and HCl. Number of moles of NaOH required to neutralize the solution formed by adding 1 mol of SO2Cl2 to excess water is:

The correct option is D 4SO2Cl2+2H2O→H2SO4+2HClH2SO4≡2NaOH2HCl≡2NaOH=4NaOHHence, the number of moles of NaOH required to neutralize the solution formed by adding 1 mol of SO2Cl2 to excess water is 4.

Sulphuryl chloride $(S O_{2} C l_{2})$ reacts with water to give a mixture of $H_{2} S O_{4}$ and $H C l$ . Number of moles of $N a O H$ required to neutralize the solution formed by adding $1$ mol of $S O_{2} C l_{2}$ to excess water is: