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Stoichiometric Calculations

Sulfuryl chlo...

Question

Sulfuryl chloride $(S O_{2} C l_{2})$ reacts with water to give a mixture of $H_{2} S O_{4}$ and HCl. How many moles of baryta would be required to neutralize the solution formed by adding 1 mole of $S O_{2} C l_{2}$ to excess of water ?

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Solution

The correct option is A
4

$S O_{2} C l_{2} + 2 H_{2} O \to H_{2} S O_{4} + 2 H C l$

$H_{2} S O_{4} + B a (O H)_{2} B a r y t a \to B a S O_{4} + 2 H_{2} O$

$2 H C l + B a (O H)_{2} \to B a C l_{2} + 2 H_{2} O$

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