Explain, why one can jump higher on the surface of moon than on the earth?

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Solution

Acceleration due to gravity at the surface of the Earth=g= $\frac{G M}{R^{2}}$
Acceleration due to gravity at the surface of the moon is $g^{'} = \frac{G M^{'}}{R^{' 2}} \frac{g^{'}}{g} = \frac{M^{'} R^{2}}{R^{' 2} M} < 1 ∴ g^{'} < g$

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Explain, why one can jump higher on the surface of moon than on the earth?

Acceleration due to gravity at the surface of the Earth=g=GMR2Acceleration due to gravity at the surface of the moon is g′=GM′R′2g′g=M′R2R′2M<1∴g′<g

Acceleration due to gravity at the surface of the Earth=g= $\frac{G M}{R^{2}}$
Acceleration due to gravity at the surface of the moon is $g^{'} = \frac{G M^{'}}{R^{' 2}} \frac{g^{'}}{g} = \frac{M^{'} R^{2}}{R^{' 2} M} < 1 ∴ g^{'} < g$