Express 0.8+0.¯¯¯7+0.4¯¯¯3 in the form pq, where p and q are integers and q≠0.
18190
We have0.8=810
Let x=0.7777..... ....(1)
∴10x=7.¯¯¯7 ....(2)
Subtracting (1) from (2), we get
9x=7⇒x=79 or 0.¯¯¯7=79
Now, let y=0.4¯¯¯3 = 0.4333....
∴10y=4.¯¯¯3 .... (3)
And 100y =43.¯¯¯3 ....(4)
Subtracting (3) and (4), we get
90y=39⇒ y= 3990
∴0.4¯¯¯3 = 3990
Now, 0.8+0.¯¯¯7+0.4¯¯¯3 = 810+79+3990
=72+70+3990 = 18190
So, 18190 is of the form pq and q≠ 0.