The correct option is B 18190
We have 0.8=810
Let x=0.¯¯¯7=0.777... ....(1)
∴10x=7.¯¯¯7 ....(2)
Subtracting (1) from (2), we get
9x=7⇒x=79 or 0.¯¯¯7=79
Now, let y=0.4¯¯¯3=0.4333....
∴10y=4.¯¯¯3 .... (3)
And 100y=43.¯¯¯3 ....(4)
Subtracting (3) and (4), we get
90y=39⇒y=3990
∴0.4¯¯¯3=3990
Now, 0.8+0.¯¯¯7+0.4¯¯¯3=810+79+3990
=72+70+3990=18190
So, 18190 is of the form pq and q≠ 0.