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Question

Express 0.8+0.¯¯¯7+0.4¯¯¯3 in the form pq, where p and q are integers and q0.

A
90182
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B
18090
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C
18190
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D
18290
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Solution

The correct option is C 18190
We have 0.8=810
Let x=0.¯¯¯7=0.777... ....(1)
10x=7.¯¯¯7 ....(2)
Subtracting (1) from (2), we get
9x=7x=79 or 0.¯¯¯7=79
Now, let y=0.4¯¯¯3=0.4333....
10y=4.¯¯¯3 .... (3)
And 100y=43.¯¯¯3 ....(4)
Subtracting (3) and (4), we get
90y=39y=3990
0.4¯¯¯3=3990
Now, 0.8+0.¯¯¯7+0.4¯¯¯3=810+79+3990
=72+70+3990=18190
So, 18190 is of the form pq and q 0.

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