Question

Express $\frac{-36}{48}$in its standard form.

Answer 1

Given,$\frac{-36}{48}$

A rational number is said to be in its standard form if its denominator is a positive integer and the numerator and denominator have no common factor other than$1$

To reduce a rational number to its standard form we divide its numerator and denominator by their highest common factor.

Since $HCFof(36,48)=12$

Thus,

$\frac{-36}{48}=\frac{-36÷12}{48÷12}=\frac{-3}{4}$

Hence, the required standard form is $\frac{-3}{4}$