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Question

Express i3j+4k as the linear combination of the vectors 2i+j4k,2ij+3k is 3i+j2k

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Solution

¯i3¯j+4¯¯¯k=x(2¯i+¯j4¯¯¯k)+y(2¯i¯j+3¯¯¯k)+z(3¯i+¯j2¯¯¯k)¯i3¯j+4¯¯¯k=(2x+2y+3z)¯i+(xy+z)¯j+(4x+3yz)¯¯¯k2x+2y+3z=1xy+z=34x+3y2z=42x+2y+3z=12x2y+2z=6––––––––––––––––––––3x3y+3z=94x+3y2z=4––––––––––––––––––––4x+5z=7x+z=5xz=54x+5z=74x4z=20–––––––––––––––9z=27z=3x=24+2y9=1y=2¯i3¯j+4¯¯¯k=2(2¯i+¯j4¯¯¯k)+2(2¯i¯j+3¯¯¯k)3(3¯i+¯j2¯¯¯k)

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