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Question

exxx log x2+2 log x dx

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Solution

Let I=exxxlogx2+2logxdx=exlogx2+2logxxdxHere, f(x)=logx2f'(x)=2logxxput exf(x)=texlogx2=tDiff both sides w.r.t xexlogx2+ex2logxxdx=dtI=dt=t+C=exlogx2+C

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