F-0- - R- fx- x 3 - 2x 2 -2x at x-5 is

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Higher Order Derivatives

f:0,∞ → R, f...

Question

$f : (0, \infty) \to R, f (x) = x^{3} - {2 x}^{2} + 2 x$ at $x = 5$ is

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x^{3} - 2 x^{2} - 2 x + 3 = 0

x^{3} - 8 x^{2} + 16 x - 9 = 0

f (x) = 0

f (\sqrt{x}) = 0

f : R \to R

f (x) = 2 x + 5

x > 0; f (x) = 3 x - 2

x \leq 0 :

f

f (x) = x^{3} - 2 x^{2} + 3 x - 5

f [sin (\frac{5 π}{2})] + f [sin (\frac{3 π}{2})] =

f : [- 2, 3] \to R

g : [0, 5] \to R

f (x) = x^{3} - x, g (x) = x^{3} - 2 x^{2} .

\frac{f (x)}{g (x)}

f (x) = 2 x^{2} + 3 x - 5

x = - 1

f^{'} (0) + 3 f^{'} (- 1) = 0

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