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Byju's Answer
Standard XII
Chemistry
Heat of Formation
F 2 g+2HClg⟶ ...
Question
F
2
(
g
)
+
2
H
C
l
(
g
)
⟶
2
H
F
(
g
)
+
C
l
2
(
g
)
Δ
H
o
=
−
352.18
k
J
Δ
H
o
f
(
H
F
)
=
−
268.3
k
J
The heat formation of
H
C
l
will be:
A
−
22
k
J
m
o
l
−
1
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B
88
k
J
m
o
l
−
1
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C
−
92.21
k
J
m
o
l
−
1
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D
−
183.8
k
J
m
o
l
−
1
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Solution
The correct option is
D
−
92.21
k
J
m
o
l
−
1
Δ
H
o
f
(
H
F
)
=
−
268.3
k
J
Δ
H
o
r
e
j
e
c
t
i
o
n
=
2
Δ
H
o
f
(
H
F
)
−
2
Δ
H
o
f
(
H
C
l
)
−
352.18
=
2
×
(
−
268.3
)
−
2
x
x
=
−
92.21
k
J
m
o
l
−
1
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0
Similar questions
Q.
2
H
C
l
(
g
)
+
F
2
(
g
)
⟶
2
H
F
(
g
)
+
C
l
2
(
g
)
Given,
Δ
G
o
∫
(
H
C
l
)
g
=
−
273
k
J
m
o
l
−
1
;
Δ
G
o
∫
(
H
F
)
g
=
−
95.5
k
J
m
o
l
−
1
The value of
Δ
G
o
for the reaction at
25
o
C
(in
k
J
) is
x
, then
x
is ________.
Q.
The heat of formation for a compound in the following reaction.
H
2
(
g
)
+
C
l
2
(
g
)
→
2
H
C
l
(
g
)
+
44
k
c
a
l
m
o
l
−
1
Q.
The enthalpy changes for the following processes are listed below:
C
l
2
(
g
)
⟶
2
C
l
(
g
)
;
Δ
H
o
=
242.3
k
J
m
o
l
−
1
I
2
(
g
)
⟶
2
I
(
g
)
;
Δ
H
o
=
151.0
k
J
m
o
l
−
1
I
C
l
(
g
)
⟶
I
(
g
)
+
C
l
(
g
)
;
Δ
H
o
=
211.3
k
J
m
o
l
−
1
I
2
(
s
)
⟶
I
2
(
g
)
;
Δ
H
o
=
62.76
k
J
m
o
l
−
1
Given that the standard states for iodine and chlorine are
I
2
(
s
)
and
C
l
2
(
g
)
, the standard enthalpy of formation for
I
C
l
(
g
)
is:
Q.
If,
H
2
(
g
)
+
C
l
2
(
g
)
→
2
H
C
l
(
g
)
;
Δ
H
o
=
−
44
K
c
a
l
2
N
a
(
s
)
+
2
H
C
l
(
g
)
→
2
N
a
C
l
(
s
)
+
H
2
(
g
)
;
Δ
H
=
−
152
K
c
a
l
Then,
N
a
(
s
)
+
0.5
C
l
2
(
g
)
→
N
a
C
l
(
s
)
;
Δ
H
o
=
?
Q.
The heat of formation HCl(g) from the reaction
H
2
(
g
)
+
C
l
2
(
g
)
→
2
H
C
l
(
g
)
;
Δ
H
=
−
44
kcal is:
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