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Preparation of Hydrogen

F2 oxidises ...

Question

$F_{2}$ oxidises $K H S O_{4}$ to $K_{2} S_{2} O_{8}$ . The change in oxidation state of $S$ from reactant to product is ___________.

A

2 units

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B

4 units

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C

no change

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D

one unit

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Solution

The correct option is C one unit
$2 K H S O_{4} + F_{2} \to K_{2} S_{2} O_{8} + 2 H F$
Oxidation state of $S$ in $K H S O_{4}$ is $6 +$ and in $K_{2} S_{2} O_{8}$ is $7 +$ .

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