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Question

f the graph of the antiderivative F(x) of f(x)=log(logx)+(logx)2
passes through (e,1998e) then the term independent of x in F(x) is

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Solution

Antiderivative of f(x)=F(x)=(log(logx)+(logx)2)dx+C
=xlog(logx)xxlogxdx+(logx)2dx+C=xlog(logx)[x(logx)1+(logx)2dx]+(logx)2dx+C=xlog(logx)x(logx)1+C
For point (e,1998e), we get
1998e=e.0e+CC=1998

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