Fx-cos 2x-sin 2x at x-12

f(x)=cos ^2 x sin ^2 x cos xcos x sin xsin x cos(x+x)=cos 2x f(π12)=cos 2 (π12) cos(π6)=√(3)2 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Monotonically Increasing Functions

fx=cos 2x-sin...

Question

$f (x) = {cos}^{2} x - {sin}^{2} x$ at $x = \frac{π}{12}$

Open in App

Solution

Suggest Corrections

Similar questions

f (x) = ∣ ∣ ∣ ∣ ∣ \begin{matrix} {sin}^{2} x & - 2 + {cos}^{2} x & cos 2 x 2 + {sin}^{2} x & {cos}^{2} x & cos 2 x {sin}^{2} x & {cos}^{2} x & 1 + cos 2 x \end{matrix} ∣ ∣ ∣ ∣ ∣, x \in [0, π] .

f (x)

\frac{\sin x}{e^{x}}

{e^{1 - x}}^{2}

f (x) = \frac{x}{2} - \sin \frac{π x}{6} on [- 1, 0]

f (x) = \frac{6 x}{π} - 4 \sin^{2} x on [0, π / 6]

[0, \frac{π}{2}]

\frac{{cos}^{2} x}{{sin}^{2} x + 4 {cos}^{2} x} o n [0, π / 2]

f (x) = \frac{{cos}^{2} x}{{sin}^{2} x + 4 {cos}^{2} x}

[0, π / 2]

Join BYJU'S Learning Program