wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

f(x)=f(x),f(0)=1, then dxf(x)+f(x)

A
log(e2x+1)+C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
log(ex+ex)+C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
tan1(ex)+C
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
None
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B tan1(ex)+C
Given that f(x)=f(x)
f(x)f(x)dx=dx
lnf(x)=x+C
when x=0, f(0)=1
Therefore, C=0
f(x)=ex
now, dxf(x)+f(x)=dxex+ex
=exdx1+e2x
=tan1ex+c
Ans: C

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon