Fx - 4x-3- x-1 x2 x- 1- thenx- 1lim fx -

X→ 1^ lim f(x) = x→ 1^ lim (4x 3) = 1 x→ 1^+lim f(x) = x→ 1^+limx^2 = 1 Since LHL = RHL ⇒x→ 1lim f(x) = 1 ...

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Existence of Limit

fx = 4x-3, ...

Question

$f (x) = {\begin{matrix} 4 x - 3, & x < 1 x^{2} & x \geq 1 \end{matrix},$ then
$lim x \to 1 f (x) =$

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Solution

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