$f (x) = tan x, 0 \leq x \leq \frac{π}{4}$ .

Open in App

Solution

$f (x) = tan x, 0 \leq π / 4$
$f (0) = tan 0 = 0$
$f (π / 4) = tan (π / 4) = 1$
$f = [0, 1], x ϵ [0, π / 4]$

Suggest Corrections

Similar questions

f (x) = \frac{1 - tan x}{4 x - π}, x \neq \frac{π}{4}, x \in [0, \frac{π}{4}]

f (x)

[0, \frac{π}{2}]

f (\frac{π}{4})

f (x) = \frac{1 - tan x}{4 x - π}

x \neq π / 4

x \in [0, \frac{π}{2}]

f (x)

[0, \frac{π}{2}]

f (\frac{π}{4})

f (x) = ⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩ \begin{matrix} \begin{matrix} {(1 - | tan x |)}^{a / | tan x |}, & - \frac{π}{4} < x < 0 \end{matrix} \begin{matrix} b, & x = 0 \end{matrix} \begin{matrix} e^{\frac{sin 3 x}{sin 2 x}}, & 0 < x < \frac{π}{4} \end{matrix} \end{matrix}

x = 0

f (x) = \frac{1 - tan x}{4 x - π}, x \neq \frac{π}{4}

lim x \to \frac{π}{4} f (x) =

The function $f (x) = tan x$ where $x \in (\frac{- π}{4}, \frac{π}{4})$ .

Join BYJU'S Learning Program