Factor the trinomial completely : $3 x^{3} + 9 x^{2} - 30 x$

3 x (x - 2) (x + 5)

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(3 x^{2} + 6 x) (x - 5)

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3 x (x + 2) (x - 5)

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(x - 2) (3 x^{2} + 15)

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Solution

The correct option is A $3 x (x - 2) (x + 5)$
$3 x^{3} + 9 x^{2} - 30 x = 3 x (x^{2} + 3 x - 10)$

= $3 x (x^{2} + 5 x - 2 x - 10)$

= $3 x [x (x + 5) - 2 (x + 5)]$

= $3 x (x + 5) (x - 2)$

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