X y x2+ y2 (x y) (x² y²) = gt; (x y) (x+y)(x y) Taking (x y) as common outside = gt; (x y)(1 x + y) ...

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Byju's Answer

Standard IX

Mathematics

Identity (x-y)^2

Factories:x-y...

Question

Factories:

x - y - x²+ y²

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Solution

x - y - x²+ y²

(x-y) -(x² - y²)

=> (x-y) - (x+y)(x-y)
Taking (x-y) as common outside

=> (x-y)(1-x + y)

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Factories: x - y - x​​​​​​2+ y​​​​​​2

x - y - x​​​​​​2+ y​​​​​​2 (x-y) -(x² - y²) => (x-y) - (x+y)(x-y) Taking (x-y) as common outside => (x-y)(1-x + y)

Factories:

x - y - x²+ y²

x - y - x²+ y²

(x-y) -(x² - y²)

=> (x-y) - (x+y)(x-y)
Taking (x-y) as common outside

=> (x-y)(1-x + y)