Factorise : $1 - 25 (a + b)^{2}$

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Solution

$1 - 25 (a + b)^{2} = (1)^{2} - [5 (a + b)]^{2} = [1 + 5 (a + b)] [1 - 5 (a + b)] = (1 + 5 a + 5 b) (1 - 5 a - 5 b)$

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1 - 25 (a + b)^{2}

Question 92 (vii)

Factorise the following using the identity $a^{2} - b^{2} = (a + b) (a - b) .$

$25 a x^{2} - 25 a$

27 a^{3} - \frac{27}{5} a^{2} + \frac{9}{25} a - \frac{1}{125}

25 a^{2} - 9 b^{2}

Factorise:

25a^2-35a+12

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