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Question

Factorise: 1+64x³

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Solution

The GENERAL pattern is:
A^3 + B^3 = (A +B) (A^2 - AB + B^2)
here 1+64x^3 can writtens
1^3+4^3x^3
=1+(4x)^3
here A=1 and B= 4X
(1+4X)(1^2-4X+64X^2)

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