Factorise:
$12 (2 x - 3 y)^{2} - 16 (3 y - 2 x)$

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Solution

We have: $12 (2 x - 3 y)^{2} - 16 (3 y - 2 x)$
$= 12 (2 x - 3 y)^{2} + 16 (2 x - 3 y)$
$= (2 x - 3 y) (12 (2 x - 3 y) + 16)$
$= (2 x - 3 y) (24 x - 36 y + 16)$
$∴ 12 (2 x - 3 y)^{2} - 16 (3 y - 2 x) = (2 x - 3 y) (24 x - 36 y + 16)$

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12 (2 x - 3 y)^{2} - 16 (3 y - 2 x)

Factorization:

$9 (2 x - 3 y)^{2} - 12 (2 x - 3 y) (2 x + 3 y) + 4 (2 x + 3 y)^{2}$

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Factorize the given expression:

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