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Question

Factorise:16x216x+4

A
(4x2)(4x2)
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B
(4x2)(4x+2)
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C
(2x4)(2x4)
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D
(2x4)(2x+4)
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Solution

The correct option is A (4x2)(4x2)
Given: 16x216x+4=(4x)22×(4x)×2+(2)2
Comparing this with the identity:
a22ab+b2=(ab)24x=a and 2=b So, (4x)22×(4x)×2+(2)2=(4x2)2=(4x2)(4x2)

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