Factorisation of Algebraic Expressions Using Identities
Factorise : 1...
Question
Factorise:16x2−16x+4
A
(4x−2)(4x−2)
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B
(4x−2)(4x+2)
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C
(2x−4)(2x−4)
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D
(2x−4)(2x+4)
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Solution
The correct option is A(4x−2)(4x−2) Given: 16x2−16x+4=(4x)2−2×(4x)×2+(2)2 Comparing this with the identity: a2−2ab+b2=(a−b)2⇒4x=aand2=bSo,(4x)2−2×(4x)×2+(2)2=(4x−2)2=(4x−2)(4x−2)