Question

Factorise:
$21x^2-2x+\frac{1}{21}$

Answer 1

$21x^2-2x+\frac{1}{21}$

$=21x^2-x-x+\frac{1}{21}$

$=x(21x-1)-\frac{1}{21}(21x-1)=(x-\frac{1}{21})(21x-1)$

So, the factors of given equation are $(x-\frac{1}{21})$ and $(21x-1)$