Factorise:
$24 a^{3} + 37 a^{2} - 5 a$

a (8 a - 1) (3 a - 5)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

a (8 a - 1) (3 a + 5)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

a (8 a + 1) (3 a - 5)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

a (8 a + 1) (3 a + 5)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $a (8 a - 1) (3 a + 5)$
$24 a^{3} + 37 a^{2} - 5 a$

$= a [24 a^{2} + 37 a - 5]$

$= a [24 a^{2} - 3 a + 40 a - 5]$

$= a [3 a (8 a - 1) + 5 (8 a - 1)]$

$= a (3 a + 5) (8 a - 1)$

Suggest Corrections

Similar questions

24 a^{3} + 37 a^{2} - 5 a

13 a + 26

\frac{sin A - sin 5 A + sin 9 A - sin 13 A}{cos A - cos 5 A - cos 9 A + cos 13 A} = cot 4 A

What should be subtracted from 12a – 16b to obtain -a – b?

Solve for $x$ : $3 x - 5 = 13$

Join BYJU'S Learning Program