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Factorisation by Common Factors

Factorise:2 a...

Question

Factorise:
2a + 6b − 3(a + 3b)²

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Solution

We have: $2 a + 6 b - 3 (a + 3 b)^{2}) = 2 (a + 3 b) - 3 (a + 3 b)^{2}$
$= (a + 3 b) (2 - 3 (a + 3 b))$
$= (a + 3 b) (2 - 3 a - 9 b)$
$∴ 2 a + 6 b - 3 (a + 3 b)^{2} = (a + 3 b) (2 - 3 a - 9 b)$

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Similar questions

2 a + 6 b - 3 (a + 3 b)^{2}

2 a + 6 b - 3 (a + 3 b)^{2}

= 2 (a + 3 b) - 3 (a + 3 b)^{2} [T a k i n g 2 c o m m o n f r o m 2 a + 6 b]

= (a + 3 b) {\begin{matrix} 2 - 3 (a + 3 b) \end{matrix}} [T a k i n g (a + 3 b) c o m m o n]

= (a + 3 b) (2 - 3 a - 9 b)

2 a + 6 b - 3 (a + 3 b)^{2}

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