Factorise : $2 a b^{2} c - 2 a + 3 b^{3} c - 3 b - 4 b^{2} c^{2} + 4 c$

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Solution

$2 a b^{2} c - 2 a + 3 b^{3} c - 3 b - 4 b^{2} c^{2} + 4 c = 2 a (b^{2} c - 1) + 3 b (b^{2} c - 1) - 4 c (b^{2} c - 1) = (b^{2} c - 1) (2 a + 3 b - 4 c)$

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