We have: nbsp; nbsp; nbsp; nbsp;2x+5y2 1=2x+5y2 12 #160; #160; #160; #160; #160; #160; #160; #160; #160; #160; #160; #160; ...

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Prime Factorisation

Factorise:2 x...

Question

Factorise:
(2x + 5y)² − 1

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Solution

We have:
${(2 x + 5 y)}^{2} - 1 = {(2 x + 5 y)}^{2} - {(1)}^{2} = \{(2 x + 5 y) + 1\} \{(2 x + 5 y) - 1\} = (2 x + 5 y + 1) (2 x + 5 y - 1)$

∴ ${(2 x + 5 y)}^{2} - 1 = (2 x + 5 y + 1) (2 x + 5 y - 1)$

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