CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Factorisation by Regrouping Terms

Factorise by ...

Question

Factorise by grouping method:

$x (6 x - 5 y) - 4 (6 x - 5 y)^{2}$

Open in App

Solution

$x (6 x - 5 y) - 4 (6 x - 5 y)^{2}$

= (6x - 5y)[x - 4(6x - 5y)]

= (6x - 5y)(x - 24x + 20y) [Taking (6x - 5y) common from the three terms]

= (6x - 5y)(-23x + 20y)

= (6x - 5y)(20y - 23x)

Suggest Corrections

thumbs-up

2

Similar questions

Q. Factorize the following equation by the grouping method

x (6 x - 5 y) - 4 {(6 x - 5 y)}^{2}

x (6 x - 5 y) - 4 (6 x - 5 y)^{2}

5 y^{2} + 5 y - 10

Q. Factorise:
(2x + 5y)² − 1

5 y^{2} + 5 y - 10

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Method of Common Factors

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Factorisation by Regrouping Terms

Standard VIII Mathematics

Join BYJU'S Learning Program

CrossIcon