Factorise $(2 x - y)^{2} - 14 x + 7 y - 18$

$(2 x - y + 9) (2 x - y - 2)$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$(2 x - y - 9) (2 x - y - 2)$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$(2 x - y - 9) (2 x + y + 2)$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$(2 x + y + 9) (2 x + y + 2)$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
$(2 x - y - 9) (2 x - y - 2)$

Given $(2 x - y)^{2} - 14 x + 7 y - 18$
Taking 7 common in the middle terms , we get
$\to$ $(2 x - y)^{2} - 7 (2 x - y) - 18$
Let $2 x - y = a$
$\to$ $a^{2} - 7 a - 18$
Using splitting the middle term , we get
$\to$ $a^{2} - 9 a + 2 a - 18$
$\to$ $a (a - 9) - 2 (a - 9)$
Taking (a-9) as common bracket , we get
$\to$ $(a - 9) (a - 2)$
Re-substituting for a , we get
$\to$ $(2 x - y - 9) (2 x - y - 2)$

Suggest Corrections

Similar questions

{(2 x - y)}^{2} - 14 x + 7 y - 18

y^{2} + 7 y - 144

Factorise the quadratic polynomial by splitting the middle term: y² - 4 y –21

(y^{2} + 7 y + 10) \div (y + 5)

(y^{2} + 7 y + 10) \div (y + 5)

Join BYJU'S Learning Program