Factorise $36 a^{2} - 49 b^{2}$

Open in App

Solution

Observe that $36 a^{2} = (6 a)^{2}$ and $49 b^{2} = (7 b)^{2}$ . Thus we get
$36 a^{2} - 49 b^{2} = (6 a)^{2} - (7 b)^{2} = (6 a + 7 b) (6 a - 7 b)$ .

Suggest Corrections

Similar questions

36 a^{2} - 84 a b + 49 b^{2}

Factorise:
$36 a^{2} + 36 a + 9$

36 a^{2} + 12 a b c - 15 b^{2} c^{2}

Factorise:

$4 a^{2} - 12 a + 9 - 49 b^{2}$

Factorise:

$4 a^{2} - 49 b^{2} + 2 a - 7 b$

Join BYJU'S Learning Program

Related Videos

Method of Identities

MATHEMATICS

Watch in App

Explore more

Join BYJU'S Learning Program