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Question

Factorise:
3a2−5a+2

A
(a1)(3a2)
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B
(a+1)(3a+2)
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C
(3a1)(a2)
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D
(3a1)(a+2)
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Solution

The correct option is A (a1)(3a2)
Factorizing3a25a+2,Split5aas:=3a23a2a+2=3a(a1)2(a1)=(3a2)(a1)

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