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Factorisation Using Algebraic Identities

Factorise: 3a...

Question

Factorise:

$3 a^{5} - 108 a^{3}$

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Solution

$3 a^{5} - 108 a^{3}$
= $3 a ³ (a ² - 36$ )
= $3 a ³ [(a) ² - (6) ²$ ]
= 3a³(a+6)(a-6)

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